A coin dealer, offered a rare silver coin, suspected that it might be a counterfeit nickel copy. (HELP)?
A coin dealer, offered a rare silver coin, suspected that it might be a counterfeit nickel copy. The dealer heated the coin, which weighed 13.0 g to 100°C in boiling water and then dropped the hot coin into 29.0 g of water at T = 18.0°C in an insulated coffee-cup, and measured the rise in temperature. If the coin was really made of silver, what would the final temperature of the water be (in °C)? (for nickel, s = 0.445 J/g-degC; for silver, s = 0.233 J/g-degC )
FYI, that doesn’t help me, just throwing out equations and numbers.
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Let UNITs guide you; always USE THEM in your calculation to prevent errors
Firstly, the eqn: hot coin + cold water —> warm coin and warm water
heat gained by water = heat lost by coin= spht of coin J/gC * 13.0 g * (100-T)C
heat gained by water = 29.0 g H2O * 4.186 J/gC * (T-18.0)C
heat lost for Ni coin = 0.445 J/gC * 13.0 g * (100-T)C
heat lost for Ag coin = 0.233 J/gC * 13.0 g * (100-T)C
for Ni coin: 0.445 J/gC * 13.0 g * (100-T(Ni-final) )C = 29.0 g H2O * 4.186 J/gC * (T(Ni-final)-18.0)C
SOLVE for T(Ni-final)
T (Ag-final) ~ T (Ni-final) * (0.233 J/gC / 0.445 J/gC) = ??
check by solving for T(Ag-final) the way you did T(Ni-final)
Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.