# Can you guys help me with these puzzles?

1) If a teenager and a half can eat a pizza and a half in a day and a half, how many pizzas can a dozen teenagers eat in three days?

2)You have twelve coins, one of which is counterfeit and weighs less than the legal coins. How can you use a simple balance three times to determine which coin is counterfeit?

& can you explain HOW you got the answer? Thankkss!

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How can there be a teenager and a half? Lol… anyways…

1.) 1.5 teenagers can eat 1.5 pizzas in 1.5 days.

One teenager can eat a pizza in a day and a half, or two pizzas in three days.

So they can eat 24 pizzas.

2.)One solution is to begin by labeling the coins with the letters from A to L. First, we "weigh" coins A, B, C, and D on one side of the balance and coins E, F, G, and H on the other side. If both sides weigh the same, the fake coin is either I, J, K, or L. If one side is lighter, it includes the counterfeit coin. Thus, after one weighing, we know that the counterfeit coin is one of four. Putting two of the coins from the lightest set on one side of the scale and two on the other, we learn which pair is lighter than the other, so we know which pair contains the counterfeit coin. We use the third weighing to compare these two coins—the lighter one is the counterfeit coin.

You right the question down on paper, then you rap it around a dildo, amd masturbate with it.

1.

If a teenager and a half can eat a pizza and a half in a day and a half,

how many pizzas can a dozen teenagers eat in three days?

Solution

24 pizzas.

One teenager can eat a pizza in a day and a half, or two pizzas in three days.

Five counterfeit coins are mixed with nine authentic coins. If two coins are drawn at random, find the probability that one coin is authentic and one is counterfeit.

Solution

45/91. If the counterfeit coin is chosen first, the probability is 5/14 • 9/13. If the authentic coin is chosen first, the probability is 9/14 • 5/13. The total probability is 5/14 • 9/13 + 9/14 • 5/13 = 45/91.

i have no clue wat that is sorry and by the way wat grade r u in ?

(Answer for question 1) The grammar is incorrect and really should be written, " If a teenager and one

half can eat a pizza and one half in one day and one half…" Anyhow, the answers…

1.5 teenager can eat 1.5 pizzas in 1.5 days. 1.5 written as a fraction equals 3/2 (three halves); therefore, 3/2 (three halves) teenagers eat3/2 (three halves) of pizza in 3/2 (three halves) days. There are three halves teenagers, three halves pizza, and three halves days. To find out how much each half is equal to, divide by 3. 3/2 divided by 3/1 = (invert and multiply) 3/2 x 1/3 =3/6 or 1/2 or one half teenager, one half pizza and one half day.

Each half of a teenager eats one half of a pizza in one half a day. Two halves of a teenager (or a whole teenager) will eat two halves (or one whole) pizza in two halves(or one whole) of a day. Therefore, 12 teenager will eat 12 pizzas in one day, 24 pizzas in two days, and 36 pizzas in three days.

(Answer for question 2)

1. Put six coins one one side of the balance and the other six one the other side. The side that holds the counterfeit will weigh less and be higher than the other side.

2. Take the six coins that hold the counterfeit (the higher side on the balance) and put three one one side and three on the other side. The side with the counterfeit will be higher because it will be lighter.

3. Take the three coins from the lighter side and put one on each side of the balance. It does not matter which two you balance because only two things can happen, and either will reveal the counterfeit coin. The coins will balance or the coins will not balance.

If the scale balances, both coins weigh the same and are genuine. The coin not used is fake.

or

If one of the coins being balanced is lighter than another, that one is the counterfeit. The coin not being used is real. Good luck.