# Counterfeit Coin Logic Problem Variation?

You have 26 weights, one of them which is slightly lighter than the other 25. How would you determine the light weight in three separate weighings on a balance scale?

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1) Weigh 9 of the weights against another 9. If one side is lighter, that set of nine has the counterfeit coin. If not, one of the remaining 8 is counterfeit.

2) Out of the group of 9 (or 8), weigh three against 3. If one side is lighter, that group of 3 has the counterfeit coin. If not, the remainint 3 (or 2) has it.

3) Out of the remainint 3 (or 2) coins, weight one against one. The lighter one is the counterfeit. If neither side is lighter, the other coin is the counterfeit.

1st weighing.:

9 against 9

This would determine which group of 9 or 8 contains the counterfeit.

2nd weighing:

From the subject group of nine:

3 against 3

This would determine which group of 3 or 2 contains the counterfeit.

Once the group of 3 (or 2) is determined to contain the counterfeit,

3rd weighinq

1 against 1

This is now elementary to determine the particular weight

You have to b in my problem solving class Cuz I totally typed that question in today to solve homework and I see u posted it yesterday! Lol…Thx to the two ppl who helped solve this. I was really stuck!