# the topic is math word problems?

the question says steven has 9 gold coins that are identical in appearance. However, one coin is counterfeit and weighs slightly less than the others. Using a balance scale, how can he find the counterfeit coin in just two weighing.? can anyone help me solve this because it is due tomorrow and thanks.

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Step one) Divide into three piles of three and weigh two of the piles. If they weigh the same the counterfeit is in the third pile.

Step two) Weigh two of the coins from the third pile and one will either be lighter (the counterfeit coin) or they will weigh the same and the counterfeit coin is the unweighed one.

Now if returning to step one, if one of the original piles of three weighs light simply apply the second step to the lighter pile.

using a balance scale, with 8 real gold coins, you would do 4 on one side, and 4 on the other side. That way, it balances out. The side though that has the counterfeit coin, will weigh more. You pick up the coins one at a time, and the one that feels lighter, is the counterfeit coin.

Place 3 coins on each side of the scale. If both sides weight the same, then the lighter coin is in the 3 coins you have not weighed. If one side weighs less, the lighter coin is in that batch.

Remove all the coins from the scale. Using the pile of 3 coins that weighed a little less, place 1 coin on one side of the scale and 1 coin on the other side. If they weigh the same, the coin you did not place on the scale is the lighter one. If one of the coins weighs less that is on the scale, then that is the lighter coin.

Hope this makes sense. Post an edit or email me if you have questions.